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Using algebra, prove that 0.136 (3,6 recurring) is equal in value to 1/33.
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One number is 4 less than 3 times a second number. if 3 more than two times the first number is decreased by 2 times the second number, the result is 11. use the substitution method. what is the first number?
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Which number can each term of the equation be multiplied by to eliminate the decimals before solving? 5.6j- 0.12=4+1.1j
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Using algebra, prove that 0.136 (3,6 recurring) is equal in value to 1/33....
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