Question 1 (1 point) 04.01 LC) Segment AB has point A located at (6,5). If the distance from A to B is 5 units, w For point B? Оа 5= V(x - 6)2 + (y – 5) 5 = V(x-5)2 +(y-6) Ob 5 6) 2+(4+ 5)2

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

did you get the answer yet?

step-by-step explanation: