A teacher needs to purchase notebooks and pencils for her students. Notebooks come in packages of 6 and pencils in packages of 10. The table shows the cost of the items. What is the least amount of money the teacher can spend and have the same number of notebooks and pencils.

$31.00

Step-by-step explanation:

Given:

We need to find the LCM of 6 and 10:

Multiples of 6:  6, 12, 18, 24, 30

Multiples of 10: 10, 20, 30

Therefore, the LCM = 30

So the least number of notebooks and pencils the teacher can buy to have the same numbers of each is 30.

⇒ 30 ÷ 6 = 5 packages of notebooks

⇒ 30 ÷ 10 = 3 packages of pencils

5 packages of notebooks = 5 × $5.00 = $25.00

3 packages of pencils = 3 × $2.00 = $6.00

Therefore, the least amount of money the teacher can spend to have the same number of notebooks and pencils (30 each) is:

⇒  $25.00 + $6.00 = $31.00

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.