Three ping-pong balls are stored in a cylinder. The cylinder has a diameter of 42 millimeters (mm) and a height of 125
mm. Each ping-pong ball has a diameter of 40
mm. The space within the cylinder, in cubic millimeters, not occupied by ping-pong balls is kπ
cubic millimeters. What is the value of k
?

answer:   rlly

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

y + 11 = (1/4)(x + 16)

step-by-step explanation: