B. At the circus, three adult tickets and five child tickets cost $51, and five adult tickets and two child tickets cost $47. Which system of linear equations below can be used to
determine the price of each ticket?
Let x represent the cost of an adult ticket, and let y represent the cost of a child ticket.

x = $7, y = $6

Step-by-step explanation:

Let x be the cost of an adult ticket

Let y be the cost of a children's ticket

Translate these sentences to algebra:

At the circus, three adult tickets and five child tickets cost $51: 3x + 5y = 51

Five adult tickets and two child tickets cost $47: 5x + 2y = 47

Now we have two equations. Let's use substitution to solve.

3x + 5y = 51

3x = 51 - 5y

.: x = 17 - 5y/3

Now substitute this value of x into the second equation to find the numerical value of y:

5(17 - 5y/3) + 2y = 47

85 - 25y/3 + 2y = 47

-19y/3 = -38

-19y = -114

.: y = 6

Now find x:

x = 17 - 5y/3

x = 17 - 10

.: x = 7

So an adult ticket costs $7, and a child ticket costs $6 :)

.

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b