The half-life of gold-195m is approximately 30.5 seconds. Step 2 of 3: How much of a 12 gram sample of gold-195m would remain after 41 seconds? Round to three decimal places.

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195

180°

step-by-step explanation:

sum of equilateral triangle=180°

< n=60°

< m=120°°[angle supplementary of equilateral angle]

< m+< r+< x=360°(sum of exterior angle of triangle)