I need help with number 3

a) 8 apples

b) 5 oranges

c) 2 oranges and 6 apples

Step-by-step explanation:

a) 8 apples × 1$ = 8$ < 10$

b) 5 oranges × 2$ = 10$

c) 2 oranges × 2$ = 4$

6 apples × 1$ = 6$ (4+6=10)

Step-by-step explanation:

The problem scenario gives rise to two equations. One describes the total number of fruit. It is plotted in blue. The other describes the total cost. It is plotted in red.

The total number of fruit will be 8 at any blue dot. (It will not cost $10 if that dot is not also red.) One such total is (4 apples, 4 oranges)

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The total cost will be $10 at any red dot. (The fruit count will not be 8 if that dot is not also blue.) One such cost is (4 apples, 3 oranges)

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The cost for 8 pieces of fruit will be $10 where the blue and red dots are plotted at the same point: (6 apples, 2 oranges)

the first one

step-by-step explanation:

just id the test.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)