the dimensions of a square are altered so that one dimension is increased by 7 feet and the other is decreased by 2 feet. The area of the resulting rectangle is 90 sq. feet. find the original area of the square

The original area of the square was 24

Step-by-step explanation:

Let's say the dimension of the new square is 9 and 10, that'll make 90

Let's say the original dimensions were 9 - 7, 10 + 2 which is 2, 12

The area of the original dimensions is 24 square feet and they altered that to make the resulting rectangle 90 square feet.

The area of the original SQUARE is 64 sq feet. x = 8

It was an 8 × 8 SQUARE.

Step-by-step explanation:

Let x = the original side length.

x + 7 is a new side

x - 2 is the other new side. Its a rectangle now.

Area of a rectangle:

A = length × width

A = (x+7)(x-2)

90 = x^2 +5x -14

Solve. Subtract 90.

0 = x^2 + 5x - 104

Factor.

0 = (x + 13)(x - 8)

x + 13 = 0 and x-8=0

x = -13 and x = 8

-13 is discarded because lengths cannot be negative.

x = 8 is the original side length of the square.

Area is 8×8 = 64 sqft

the answer is the third / last answer

step-by-step explanation: