Question: Find the vertex.

Equation: y = -x^2-6x+15

([Put Number],[Put Number])

y = (x - 3)² + 6

Step-by-step explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

Using the method of completing the square

y = x² - 6x + 15

add/subtract ( half the coefficient of the x- term )² to x² - 6x

y = x² + 2(- 3)x + 9 - 9 + 15

y = (x - 3)² - 9 + 15

y = (x - 3)² + 6 ← in vertex form

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: