write an equation of a line passing through the point (-4,11) and perpendicular to the line 4x + 5y = -45

y = 5/4x - 6

Step-by-step explanation:

First, put 4x + 5y= -45 in y = mx + b form

4x + 5y= -45

5y = -4x - 45

y = -4/5x - 9

So, the slope is -4/5. Perpendicular lines have a opposite reciprocal slope, so the line's slope will be 5/4 right so to find the equation of the perpendicular line in this question, plug in the slope and given point into y = mx + b, and solve for b

y = mx + b

-11 = 5/4(-4) + b

-11 = -5 + b

-6 = b

so you should Plug in b and the slope into y = mx + b

y = 5/4x - 6

So, the equation is y = 5/4x - 6

if this doesn't make sense i don't know what will

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

c

step-by-step explanation: