The expression 1/2mv^2 gives the kinetic energy, in joules, have an object with a mass of m kilogram traveling at a speed of v meters per second. What is the kinetic energy of an experimental unmanned jet with a mass of 1.6 times 10^3 kg traveling at a speed of about 3.2 times 10^3 m/s

8,192,000,000 KE in joules. I think

Step-by-step explanation:

1.6 x 10^3 = 1600

3.2 x 10^3 = 3200

3200^2 = 10240000

1600 x 10240000 = 1.6384E10

so then multiply that by 1/2 = 8,192,000,000 KE in joules

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)

mrbilldoesmath!

answer: a parabola

steps:

(x-1)(x+4)   = x(x+4) - 1(x+4) = (x^2 + 4x) - (x+4)

                = x^2 +4x -x -4   = x^2 +3x -4

which is a parabola

mrb