Two turtles, which are 750 meters apart, start moving toward each other. One turtle travels at an average speed of 1 km/h, and the other travels 1 km/h faster. When will the turtles meet if they started to move at 11:00 a. m.

The time at which the turtles meet if they started to move at 11:00 a.m is; 11:15 a.m

Distance between the two turtles = 750 m

First turtle travels at an average speed of 1 km/h. Thus; v₁ = 1 km/h

Second turtle travels at an average speed of 1 km/hr faster than the first. Thus; v₂ = 2 km/h

Since second turtle is moving 2 times faster than the first one, it means the second turtle will cover 2/3 of the total distance while the first will cover 1/3 of the total distance at the point they will meet.

Thus; Distance covered by turtle 2 = 2/3 * 0.750 = 0.5 km

Time = distance/speed

Time = 0.5/2 = 0.25 hours = 15 minutes

Since they both started at 11.00 a.m then they will meet at 11:15 a.m

Read more about distance, speed and time at;

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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step-by-step explanation:

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