David has 400 yards of fencing and wishes to enclose a rectangular area against a pre-existing fence. What equation should David use to help him maximize the area? A. f(x)=x(400-2x)
B. f(x)=x(400+2x)
C. f(x)=2x(400-x)
D. f(x)=2x(400+x)

f(x)=x(400-2x)

yes

step-by-step explanation:

the answer is: the length is 5/6 yards.

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step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet