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Mathematics, 22.02.2022 17:40 magalyrodette7812
Given the function f(x)=4x2β3x+4f(x)=4x2-3x+4. Calculate the following values:
f(β2)=f(-2)=
f(β1)=f(-1)=
f(0)=f(0)=
f(1)=f(1)=
f(2)=f(2)=
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Given the function f(x)=4x2β3x+4f(x)=4x2-3x+4. Calculate the following values:
f(β2)=f(-2)=
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