There are 380 light bulbs lined up in a row in a long room. Each bulb has its own switch and is currently switched off.
Each bulb is numbered consecutively from 1 to 380. You
first flip every switch. You then flip the switch on every
second bulb(turning off 2, 4,6...). You then flip the switch
on every third bulb (3, 6, 9...). This continues until you
have gone through the process 380 times.

Bulb 2 was activated 760 times throughout the process.

To calculate how many times light bulb #2 was activated, we must identify how many times it is activated in each process.

Based on the information provided, bulb two has the following activity.

According to the above, bulb #2 is activated 2 times each process. So to know how many times it is activated in total, we must multiply the number of times it is activated in each process by the total number of processes (380).

380 × 2 = 760

Note: This question is incomplete because the question is missing. Here is the question:

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-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation

for the free

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