![2sin(\theta )+\sqrt{3}=0\implies 2sin(\theta )=-\sqrt{3}\implies sin(\theta )=-\cfrac{\sqrt{3}}{2} \\\\\\ sin^{-1}\left[ sin(\theta ) \right]=sin^{-1}\left( -\cfrac{\sqrt{3}}{2} \right) \implies \theta =sin^{-1}\left( -\cfrac{\sqrt{3}}{2} \right)\implies \theta \begin{cases} \stackrel{III~Quadrant}{\frac{4\pi }{3}}\\\\ \stackrel{IV~Quadrant}{\frac{5\pi }{3}} \end{cases}](/tpl/images/2667/2337/7e6a6.png)
If 2sin theta = √3, (0° < theta <90° ), then find the value of theta
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Mathematics, 22.02.2022 14:00 alejandr1872913
If 2sin theta = √3, (0° < theta <90° ), then find the value of theta
Answers: 1
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