Hoping to lure more shoppers downtown, a city builds a new public parking garage in the central business district. The city plans to pay for the structure through parking fees. For a two-month period (44 weekdays), daily fees collected averaged $1,257, with a standard deviation of $130. Complete parts a through d. Question content area bottom Part 1 (a) What assumptions must you make in order to use these statistics for inference? Select all that apply. A. The data from the sample are not extremely skewed. The sample size is larger than 10 times the squared skewness and 10 times the absolute value of the kurtosis. Your answer is correct. B. The sample of 44 weekdays is representative of all days. C. The sample is a simple random sample from the relevant population. Your answer is correct. D. The distribution of sample weekday parking fees is nearly normal. Part 2 (b) Find a 95% confidence interval for the mean daily income this parking garage will generate, rounded appropriately for your message. The 95% confidence interval for the mean daily income is $enter your response here to $enter your response here . (Round to the nearest dollar as needed.)

it should be a and d. lmk if i'm wrong xd

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

percentage - 25%

probability - 0.25

we know,

total amount of students in class = 20

total boys = 10

total girls = 10

no of girls who wear glasses = 10/2 = 5

probability of choosing a girl with glasses is =

number of girls wearing glasses/total number of students in the class = 5/20

thus, percentage of selecting a girl wearing glasses will be

= 5/20 × 100

= 5 × 5

25%

therefore,

probability will be 0.25

happy to

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