This trapezoid has been divided into two right triangles and a rectangle. How can the area of the trapezoid be determined using the area of each shape? Enter your answers in the boxes. The area of the rectangle is _in, the area of the triangle on the left is _in, and the area of the triangle on the right is _in
The area of the trapezoid is the sum of these areas, which is _in

the area of the rectangle is 168in

the area on the triangle on the left is 12in

the area of the triangle on the right is 12in

the area of the trapezoid is the sum of these areas, which is 192in

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18