Fibonacci Variation: A single pair of rabbits (male and female) is born at the beginning of a year. Asume the following conditions (which are more realistic than Fibonacci's): 1) Rabbit pairs are not fertile during their first month of life but thereafter give birth to four new male/female pairs at the end of every month,
2) No rabbits die
a) Let rn=the number of pairs of rabbits alive at the end of month n, for each integer n>=1, and let r0=1. Find the recurrence relation for r0,r1,
b) how many rabbits will there be at the end of the year.

you going to fail stop

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

answer:

125 yards

explanation:

75+50=125. that is my answer