The standard for of the equation is y=7x^2+14x+4. What is the vertex form of the equation

7(x+1)^2 - 3

Step-by-step explanation:

To Write in The Vertex Form Simply means expressing the equation using completing of the square method

step 1: Make the coefficient of x^2 to 1

7 [x^2 + 2x + 4/7]

step 2: express the coefficient of x as half's of positive and negative

7 [x^2 + 2x + (1)^1 - (1)^1 + 4/7]

step 3: separate the negative part and the constant to solve then correct x^2 and 1^2 together

7 [ (x+1)^2 -3/7 ]

step 4 : distribute the 7

7(x + 1)^2 - 3

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

the answer is (-4,-4)

hope this ! : d