There are 4 aces and 4 kings in a standard deck of playing cards. you pick one random card at random. What is the probability of selecting an ace or king? Note: It has to be a fractaion

2/3

Step-by-step explanation:There are 52 cards in a standard deck: 13 ordinal cards (Ace - 10, Jack, Queen, King) and 4 of them - one to each suit (hearts, diamonds, clubs, spades) and so we have

4

×

13

=

52

.

There are 8 cards that fit the question (4 each of aces and kings).

And so in a random draw, the odds of drawing one of those 8 cards out of the total number of 52 is:8/52

which we can simplify:

8/52=2/13

answer: d. $20

step-by-step explanation:

just took the test

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497