Find the area of the shaded region. (You may express your answer in

terms of π.)

a. 16π cm²

b. 24π cm²

c. 33 1/3π cm²

d. 64π-128 cm²

e. 144π-288 cm²

Step-by-step explanation:

To find area of shaded region, find area of whole circle then divide the area where you're left with the area of the shaded region. For the problems with the triangles you find the area of the triangle then subtract that from a fourth of the area of the circle.

Area of a circle = πr²

a.

r=8cm

Area of circle=64π cm²

Shaded region=16π cm²

b.

r=12cm

Area of circle=144π cm²

Shaded region=24π cm²

c.

r=10cm

Area of circle=100π cm²

Shaded region=33 1/3π cm²

d.

r=16cm

Area of circle=256π cm²

Area of triangle=128 cm²

Shaded region=64π-128 cm²

e.

r=24

Area of circle=576π cm²

Area of triangle=288 cm²

Shaded region=144π-288 cm²

70,000 + 6,000 + 800 + 30

step-by-step explanation:

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: