On a standardized exam, the scores are normally distributed with a mean of 650 and a standard deviation of 25. Find the z-score of a person who scored 710 on the exam

Step-by-step explanation:

First, compute the z-score:

z = (x-μ)/σ = (650-500)/100 = 150/100 = 1.5

Now look up the percentile for z = 1.5 on a z-score table (http://www.z-table.com/).  The percentile, p(z=1.5), is the percent of people who scored 650 or less.  The percent who scored more than 650 is 1-p(z=1.5).  Multiply that by the 1200 students to get the number who scored more than 650.  Round to the nearest whole number (because you can't have a fraction of a person).

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

b

step-by-step explanation: