Please answer the question in the picture

2(3x+1)(x+1)

explanation:

→ 6x²+8x+2

→ 2(3x²+4x+1)

→ 2(3x²+3x+x+1)

→ 2(3x(x+1)+1(x+1))

→ 2(3x+1)(x+1)

2(3x + 1)(x + 1)

Step-by-step explanation:

6x² + 8x + 2

Multiply the coefficient of x² and the constant:  6 x 2 = 12

Find factors of 12 that sum to make the coefficient of x (8):  2 and 6

Therefore,

  6x² + 8x + 2

= 6x² + 6x + 2x + 2

= 6x(x + 1)+2(x + 1)

= (6x + 2)(x + 1)

= 2(3x + 1)(x + 1)

tangent

step-by-step explanation: