How do you write an equation of a line so that it is parallel or perpendicular to a given point? Explain both

to find parallel;

first of all, parallel equations should have the same slope and a different y-intercept!

when were given a point (x,y), we write our equation in the y = mx + b form, then substitute the given point for (x,y) and solve for B!

However, to find the slope of the perpendicular equation, you need to get the negative reciprocal of the slope!

For example, if the slope is 3 in the original equation, it would be - 1/3 in perpendicular equation.

We then substitute the given point for (x,y)!

hope this helps :)

Leave a comment if you need further explanation

Step-by-step explanation:

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i

60°

step-by-step explanation:

the measure angle of c in an isosceles triangle abc is 60° because in isosceles triangle,the measures of all the angles is 60°.