Suppose you have 20 coins that total $3.00. Some coins are nickels and 1 point some are quarters. Which of the following pairs of equations can you use to
find how many of each coin you have?

n + q = 20

5n + 25q = 300 or 0.05n + 0.25q = 3

Step-by-step explanation:

You know that you have some nickels and some quarters, and together there are 20 coins. So if n represents the number of nickels, and q represents the number of quarters, you can use this equation:

n + q = 20

You also know that together the coins total three dollars. We know that a nickel is worth 5 cents and a quarter is worth 25. So if n and q still represent the number of each type of coin, we can use this equation:

5n + 25q = 300

or

0.05n + 0.25q = 3

The reason I said 300 in the first equation is because you are counting the number of cents. There are 300 cents in 3 dollars.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb