Two fire-lookout stations are 25 miles apart, with station B directly east of station A Both stations spot a fire. The bearing of the fire from station A is N35°E and the bearing of the fire from station B is N30°W. How far, to the nearest tenth of a mile, is the fire from each lookout station?

i think it would be c

mark brainliest if im right

step-by-step explanation:

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation:

ιт ιѕ (9χ^5+10)(81χ^10-90χ^5+100)

step-by-step explanation:

нσρє ι ¢συℓ∂ нєℓρ уσυ συт тσ∂α