An ocicat eats 3/5 of a pound of food daily. How many ocicats can a 19 1/2-pound bag of food feed for one week? Explain your solution.
Really need a good explanation

13 Ocicats

Step-by-step explanation:

Here, we are told that an Ocicat eats 3/5 pounds of food per day.

Now, we have a bag of 19 1/2 pound of food and we want to know the number of Ocicats this will feed

What we just need to do is to divide the weight of the bag by the amount in pounds that can feed a single Ocicat

Thus, we have;

19 1/2 divided by 3/5

= 39/5 divided by 3/5

= 39/5 * 5/3

= 13 Ocicats

A 19 1/2 lb of food will feed 4 ocicats for a week and will have 9/14 lb left.

Step-by-step explanation:

The bag contains 19 1/2 lb of food.

One ocicat eats 3/5 lb in 1 day.

To find how many days you can feed 1 ocicat with 19 1/2 lb of food, we divide 19 1/2 lb by 3/5 lb.

19 1/2 ÷ 3/5 = 39/2 × 5/3 = 65/2 = 32.5

The food in 1 bag is enough to feed an ocicat 32.5 days.

A week has 7 days.

32.5/7 = 65/2 × 1/7 = 65/14 = 4 9/14

A 19 1/2 lb of food will feed 4 ocicats for a week and will have 9/14 lb left.

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1