3^2y-1 = (9)(27)^y-2 calculate the value of y

Thank you

y = 3

Step-by-step explanation:

3^2y - 1 = (9)(27)^y - 2

3^2y-1 = 243^y - 2

log(243)/log(3) = 5

2y - 1 = 5(y - 2)

2y - 1 = 5y - 10

-5y      -5y

-3y - 1 = -10

     + 1    +1

-3y = -9

-3      -3

y = 3

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}