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5/9 (v-1)

Step-by-step explanation:

2/9v-1(-1/3v+5/9) ~ eliminate redundant parentheses

2/9v+1/3v-5/9 ~ distribute

5/9v-5/9 ~ combine like terms (factor by grouping)
5/9(v-1) ~ common factor

solution: 5/9(v-1)

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v