At an ocean depth of 20 meters, a buoy bobs up and then down 2 meters from the oceans depth. Four seconds pass from the time the buoy is at it's highest point to when it is at lowest point. Assume at x=0, buoy is at normal ocean depth Use the sine tool to graph the function. The first pint must be in the midline and the second must be a maximum or minimum value on the graph closest to the first point

We'll use a sin graph since at x=0 the buoy is at the y midline

the period is 8 seconds  (highest point to lowest point and back to highest point)

Frequency is   1/period     1/8

Starts at 20  (sine wave shifted up 20 m)

Amplitude  2   (up 2 meters then down 2 meters below norma ocean depth)    ( I think this is what you meant in your questionif it bobs UP 2m then back to normal depth then down 2m)

2sin((2pi x)/8)   + 20

Step-by-step explanation:

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it