At an ocean depth of 20 meters, a buoy bobs up and then down 2 meters from the oceans depth. Four seconds pass from the time the buoy is at it's highest point to when it is at lowest point. Assume at x=0, buoy is at normal ocean depth Use the sine tool to graph the function. The first pint must be in the midline and the second must be a maximum or minimum value on the graph closest to the first point

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

um is there supposed to be a picture?