The bull’s-eye on a target has a diameter of 5 inches. The whole target has a diameter of 13.5 inches. What part of the whole target is the bull’s-eye? Enter your answer as a decimal.

13.71% or rounded we have 14%

Step-by-step explanation:

We need to find the area so we need to use the formula of Area = piR^2

>> Area of bulls-eye = π(2.5)^2 = 19.63in^2

>> Area of whole target = π(6.75)^2 = 143.13in^2

NOTE: The target values above are halved values of 5 and 13.5

Now, all we have to do is divide the area of the bullseye by the area of the target, so some simple stuff.

19.63/143.13 > 0.13714804 > In a percent we have 13.71% or rounded we have 14%

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.