HEP PLEASE THIS IS DUE TODAY AND I DON'T GET IT AT ALL 1) Given: GHJN and JKLM are parallelograms and angle HJN and KJM touch.
Prove: angle G = angle L

2) Given: PSTV is a parallelogram inside triangle PQR.
Prove: angle STV = angle R

3) Given: ABCD and AFGH are parallelograms. (AFGH is smaller and inside of ABCD)
Prove: angle C = angle G

4) Given: PQRS is a parallelogram. PR is perpendicular to QS and both diagnals are inside PQRS, meeting at the angles.
Prove: PQRS is a rhombus

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)