Mathematics, 08.02.2022 01:00 SkinnestXOXO
Let 0 be an angle in quadrant III such that sin 0 =-8/17 Find the exact values of sec 0 and cot 0.
Answers: 2
![sin(\theta )=\cfrac{\stackrel{opposite}{-8}}{\underset{hypotenuse}{17}}\qquad \qquad \textit{let's find the \underline{adjacent} side} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{17^2-(-8)^2}=a\implies \pm\sqrt{225}=a\implies \pm 15=a\implies \stackrel{III~Quadrant}{-15=a} \\\\[-0.35em] ~\dotfill](/tpl/images/2649/3495/a9a03.png)
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Let 0 be an angle in quadrant III such that sin 0 =-8/17
Find the exact values of sec 0 and cot 0....
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