![y = ab^t \\\\[-0.35em] ~\dotfill\\\\ \underset{t=0\hfill }{6300=ab^0}\implies 6300-a(1)\implies 6300=a~\hfill \underline{y=6300b^t} \\\\[-0.35em] ~\dotfill\\\\ \underset{t=4\hfill }{8200=6300b^4}\implies \cfrac{8200}{6300}=b^4\implies \cfrac{82}{63}=b^4\implies \sqrt[4]{\cfrac{82}{63}}=b \\\\\\ ~\hfill \underline{y=6300\left( \sqrt[4]{\frac{82}{63}} \right)^t} \\\\[-0.35em] ~\dotfill\\\\ \textit{when t = 13}\qquad \qquad y=6300\left( \sqrt[4]{\frac{82}{63}} \right)^{13}\implies y\approx 14838.1168](/tpl/images/2649/2944/d400a.png)
Don cheTD invested $ 6,300 in Account in the
year 20066, Its been reached $8,200 in 2010
Det...
Mathematics, 07.02.2022 18:40 leomessifanboy678
Don cheTD invested $ 6,300 in Account in the
year 20066, Its been reached $8,200 in 2010
Determine the value of the account in 2019
Answers: 2
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