The sum of two numbers is 57. The larger number is three less than four times the smaller number. Find the numbers pls help i am timed

The numbers are 10.8 and 46.2.

Step-by-step explanation: The sum of two numbers is 57.

x + y = 57

Assume x is the larger number.

x - 3 = 4y

x = 4y + 3

Use subsitution.

4y + 3 + y = 57

y = -4y - 3 + 57

y = -4y + 54

5y = 54

y = 10.8

Plug in y.

x + 10.8 = 57

x = 46.2

Check.

46.2 - 3 = 4(10.8)

43.2 = 43.2

10.8 and 46.2.

Step-by-step explanation:

the answer to this question is 3/19

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.