PLEASE HELP You pick a card at random. Without putting the first card back, you pick a second card at
random
5 6 7 8
9
What is the probability of picking an even number and then picking an even number?
Write your answer as a fraction or whole number.

The probability of picking 7 and then picking a number greater than 7 is or 0.3

Step-by-step explanation: Probability

Probability shows us the chances of an event occurring.

Now, given that we have already picked three cards. therefore, 7, 8, and 9.

The number of possible outcomes is 3.

the probability of card 7,

Now, as card seven is already picked up cards 8 and 9 are the only card left.

therefore, the sample size(possible outcomes) was reduced to 2 only.

Also, cards 8 and 9 both are greater than 7, thus the desired outcome is also 2.

Further the probability of the number greater than 7 occurring,

Probability picking a number greater than 7

The probability of picking a 7 and then picking a number greater than 7

= Probability of card 7 occurring x probability of card 8 and 9 occurring.

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m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

step-by-step explanation: