Pls help

With the second one
A and B and the triangle

the new side lengths are 10.5 , 9 and 6 inches

the new triangle has the following sides: 5, 4, 3 inches

the perimeter of the first triangle is 36 inches

the perimeter of the second triangle is 12 inches

area of the first triangle is 54 inches squared

area of the second triangle is 6 inches squared

Step-by-step explanation:

first question:

sides are 7,6,4. multiply each one by 3/2 or 1.5

7 x 1.5 = 10.5 or 12/2

6 x 1.5 = 9

4 x 1.5 = 6

the new side lengths are 10.5 , 9 and 6 inches

second question:

multiply each side by 1/3

the sides are 15, 12, 9, so:

15 x 1/3= 5

12 x 1/3 = 4

9 x 1/3 = 3

the new triangle has the following sides: 5, 4, 3

normal sides are 3 and 4

hypotenuse is 5

question a: (calculate perimeter)

the perimeter of a triangle: you add all the sides

the first triangle has 15, 12, 9 for its sides so:

15+12+9 = 36

the perimeter of the first triangle is 36

the second triangle has 5,4,3 for its sides so:

5+4+3 = 12

the perimeter of the second triangle is 12

question b: (calculate the area of both triangles)

area of a triangle: h x b/2: height times base divided by 2

the first triangle has sides, 15,12,9

height is 9 and base is 12, so:

9 x 12/2 = 54 inches squared

area of the first triangle is 54 inches squared

the second triangle has sides, 5,4,3

height is 3 and base is 4, so:

3 x 4/2 = 6 inches squared

area of the second triangle is 6 inches squared