A paralegram is shown berw B
foot
D
С
3 feet
Part A: What is the area of the parametram Show your work (5 points)
Part B: How can you decome this pariram into two triangles? If this pararam was decomposed into two triangles, what would be the area of each
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Part A: 2 ft²

Part B: draw a diagonal (AC, for example); 1 ft²

Step-by-step explanation:

Part A:

The area of a parallelogram is given by the formula ...

A = bh

where 'b' is the length of the base, and 'h' is the perpendicular distance between the bases.

Using the numbers shown on the diagram, the area is ...

A = (3 ft)(2/3 ft) = 3·2/3 ft²

A = 2 ft² . . . . . area of the parallelogram

Part B:

Typically, a polygon is partitioned into triangles by drawing diagonals from one of the vertices. It does not matter which one. (In a quadrilateral, only one diagonal can be drawn from any given vertex.) Here, the "base" of each triangle is the same as the base of the parallelogram: 3 feet. The "height" of each triangle is the same as the height of the parallelogram: 2/3 ft.

The area of a triangle is given by the formula ...

A = 1/2bh

A = 1/2(3 ft)(2/3 ft) = (1/2)(3)(2/3) ft²

A = 1 ft² . . . . . . . . area of each triangle

Additional comment

It should be no surprise that the area of each of the two congruent triangles is 1/2 the area of the parallelogram.