Using a fair coin and a number cube with faces numbered 1 through 6, what is the probability of getting heads and rolling a 5? A
1/12
B
1/6
C
1/2
D
11/12

Step-by-step explanation:

Use Multiplication Principle with states that if a event can occur n ways, and another mutually exclusive event occur p ways, then the total outcome is

The possible ways of rolling a dice is 6 and the possible ways of flipping a coin is 2 so we have

Now, we use the fact that proabliblity is

Number of favorable outcomes/ Total outcomes.

We can only get a head and a 5 once out of the set so the number of favorable outcomes is 1. Total outcomes is 12 so we have

A is the answer.

answer: ouch. thats difficult

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?