Write an exponential function that passes through (0, 3) and (1, 6).

y=x^8-x^7+x^6-x^5+x^4+x^3+x^2+3

Step-by-step explanation:

here is an example function that satisfies the requirement:

y=x^8-x^7+x^6-x^5+x^4+x^3+x^2+3

if you plug in x=0,

you get y= 3, which satisfies (0,3)

if you plug in x=1,

you get y = 1 - 1 + 1 - 1 + 1 + 1 + 1 + 3,

you get y=6, which satisfies (1,6)

definition: a circle is the  set of all points in a plane that are equidistant  from a given  point  called the center of the circle. we use the symbol ⊙ to represent a circle. the a line segment from the center of the circle to  any point  on the circle is a radius of the circle.

step-by-step explanation:

i googled it and this is what i got i don't know how it is. sorry.

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72