A projectle is fired straight up from ground level. After t seconds, its height above the ground is s feet, where s = -16t² +96t For what time period is the projectile at least 128 feet above the ground?

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: