Please help this is due tomorrow :,)

Given

in ∆ABC

AB = 5cm

BC = 6 cm

AC = 7 cm

now,

as we have to make ∆PQR inside it

than, possibly ∆PQR's sides length is,

PQ = ½ of CB (according to mid point theorem)

→ CB = 6cm → 6/2 → 3cm

PQ = 3cm

QR = ½ of AC

→ AC/2 = 7/2 = 3.5 cm

RP = ½ of AB

→ AB/2 = 5/2 = 2.5cm

therefore, length of

PQ = 3cm

QR = 3.5 cm

PR = 2.5 cm

Hope this answer helps you dear!

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: