A ship leaves port at noon and has a bearing of S 32° W. The ship sails at 20 knots. (a) How many nautical miles south and how many nautical miles west will the ship have traveled by 6:00 P. M.? (Round your answers to two decimal places.)
miles south:
miles west:

(b) At 6:00 P. M., the ship changes course to due west. Find the ship's bearing and distance from port at 7:00 P. M. (Round your answers to one decimal place.)
S° W
nautical miles

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.

a

step-by-step explanation: