Circle the equation with a rate of change of 3. 3y = 2x + 5
y = 6x – 3
y= 3x + 12

Write as a product: ac^2–ad+c^3–cd–bc^2+bd

Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.

I'm marking the brainliest and it's 15 points