Write an equation of the line that passes through (5. – 1) and is perpendicular to the line y = 1/2x - 1 An equation of the perpendicular line is y =

y = - 2x + 9

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x - 1 ← is in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 2 , then

y = - 2x + c ← is the partial equation

To find c substitute (5, - 1 ) into the partial equation

- 1 = - 10 + c ⇒ c = - 1 + 10 = 9

y = - 2x + 9 ← equation of perpendicular line

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?