After spending the day building sand castles, Oceana wants to take an evening walk with
a friend along the shoreline.
Oceana knows that one stretch along the
shore is quite rocky. At that point, the rocks
jut into the ocean. To walk around them,
a person has to follow a path that is 14 feet
below the average waterline.
If Oceana and her friend don’t want to get
wet, they need to take their walk when the
waterline is 14 feet or more below the average
waterline. What is the time period during
which they can take their walk?
Remember that the position of the waterline
over the course of the day is given by the
equation w(t) 5 20 sin (29t), where the
distance is measured in feet and t represents
the number of hours elapsed since midnight.

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

you would 18 *0.25 = 4.5

im not preaty sure about that

step-by-step explanation: ax^2+bx+c=0= these nuts