Given: AABC, m_ACB=90°,
CD 1 AB, m ZACD=60º,
BC = 6 cm
Find: CD, Area of AABC

it would open into a square depending on the type of envelope i’m not sure about the second part

sorry i got nothing

step-by-step explanation:

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

im guessing (23,14). hope this : )