Find the value of k such that the equation (k+4) x^2 + 2(k+1)x +(k-1)= 0 has equal roots

b^2-4ac(formula for finding the roots )

Step-by-step explanation:

1)9-4k=0

k=9/4(roots are real )

2)4-4k+4=0

8-4k=0

k=2(the roots are real )

3)64-8k=0

k=8

4)36-16k+16=0

52-16k=0

k=52/16=13/8

16-4k+4=0

k=5

Step-by-step explanation:

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

about 168 miles

step-by-step explanation: